Need some math help..come in if you think you can

[grouch0jr]

It is needed in college algebra and and absolute requirement for any math above college algebra. You can even have games on it! (I typically play Dope Wars.)

I'm guessing you're in 0305? In 0310 I believe is when you start figuring Square Roots in Linear Inequalities. Get a graphing calculator.

in most of my college level classes we werent allowed to use calculators because it was too easy to cheat

[Tonik]

in most of my college level classes we werent allowed to use calculators because it was too easy to cheat

You'd only be hurting yourself in the later classes. In calculus if you don't have a good solid algebra base you will fail. miserably.

[grouch0jr]

You'd only be hurting yourself in the later classes. In calculus if you don't have a good solid algebra base you will fail. miserably.

right, thats why we couldnt use calculators

[Tonik]

right, thats why we couldnt use calculators

well... uhhh...

my professors are cooler than yours?

[ninobrn99]

Tomorrow Im gonna look over my quiz before I turn it in. I may post up a few of the questions that Im shaky on.

[ninobrn99]

this ones not so bad either. slope intercept form is:
y=mx+b
m is the slope and b is your y intercept. (when the line crosses the y axis, x will be equal to zero and cancel the m term).
so you already have your b, the y intercept.
y=mx+3/2
now you need to solve for m. youre given 2 points, the x intercept (-2,0) and the y intercept (0,3/2).
there are 2 ways to solve for the slope. first, is to calculate it using the two points. slope is defined as "rise over run", or the change in y divided by the change in x. so the formula would be m=(y1-y2)/(x1-x2).
or, you can plug one of the points into the y=mx+3/2. you cant use the y intercept point, since x is 0 it will cancel out the m, so you have to plug in the x intercept.

y=mx+3/2
(-2,0) x=-2 y=0

0=m(-2)+3/2

solve for m
m=3/4

so y=(3/4)x+3/2

haha, its a little early in the morning for me, so if any of that is unclear let me know.

why do I keep coming up with -1/2 for my slope?
m=y1-y2/x1-x2
m=0-(3/2)/-2-0
m=(-2/1)/(3/2)
m=-1/2

Is that right?

[ninobrn99]

okay, came up with something different again
x=-2 y=0
x=0 y=3/2

m=(3/2)-0/-2-0
m=(-1.5/2)x+3/2

[grouch0jr]

why do I keep coming up with -1/2 for my slope?
m=y1-y2/x1-x2
m=0-(3/2)/-2-0
m=(-2/1)/(3/2)
m=-1/2

Is that right?

the equation for slope is:
m=(y1-y2)/(x1-x2)
the parenthesis are very important.
m=(0-3/2)/(-2-0)
m=(-3/2)/(-2)
m=(3/2)/2
m=3/4

[310stanger]

the equation for slope is:
m=(y1-y2)/(x1-x2)
the parenthesis are very important.
m=(0-3/2)/(-2-0)
m=(-3/2)/(-2)
m=(3/2)/2
m=3/4

where were you when i was in high school? haha could have used you as a tutor

[grouch0jr]

where were you when i was in high school? haha could have used you as a tutor

haha, i was 2 years behind ya

[ninobrn99]

I figured out what I was doing wrong. Now we moved on the systems of equations. So far so good. Thanks again.