What should I do?
This is a discussion on What should I do? within the Suspension and Handling forums, part of the General Help category; I'm not doubting Jon..... That is based on if you have equal mass of the material and equal quality/type of ...
09-08-2011, 01:23 PM #21
- Join Date
- Feb 2009
- Ugy Lower Corner of AL
Navy Blue Metallic
- 98 T/A w/a little mods...
I'm not doubting Jon.....
That is based on if you have equal mass of the material and equal quality/type of material. Correct Jon?
09-08-2011, 03:23 PM #22
Im not doubting either. I am just curious what they wereSuspension: Lower control arms (Spohn), Drive shaft safety loop, Torque arm (Edlebrock), Strut tower brace, Panhard Bar (BMR)
Under the Hood: Smooth bellows, Lid, Catch can, LT Headers, ORY, AIR/EGR delete, Poly engine/transmission mounts,
Exterior: Painted brake calipers (Red), Halo “Spyder” Headlights w/matching parking/turn signals (Black)
09-08-2011, 04:48 PM #23
Here is my thought process...
The area of a tube is the area of the outside diameter minus the area of the hole of the tube. So, if you have a 2" diameter tube with a 1" hole in it (1/2" thickness), the area would be:
Outside area = PI * Radius^2 = 3.14 * 1"^2 = 3.14 inches^2
Hole area = PI * Radius^2 = 3.14 * 0.5"^2 = 0.785 inches^2
Overall area = 3.14"^2 minus 0.785 inches^2 = 2.355 inches^2
Now let's look at the same size in a box (square) in a 2" by 2" that is 1/2" thick.
Area of outside of square = length X width = 2" X 2" = 4 inches^2
Area of the inside of the square (empty part) = 1" X 1" = 1 inch^2 (it's only 1" because you subtract 1/2" from each side for the thickness).
Overall area = 4 inches^2 minus 1 inch^2 = 3 inches^2
So you are now comparing 3 inches^2 of area versus 2.355 inches^2 of area.
You can also consider the moment of inertia of each piece, tubular versus a square/box and you will find that the moment of inertia of the box is higher.
Bending stress = Mc/I, where M = moment, c = distance from the neutral axis to the extreme fiber, and I = moment of inertia. So, the higher the value of I, the lower the bending stress.
09-08-2011, 04:54 PM #24
09-08-2011, 05:27 PM #25
^ what he said. That was impressive.
LS6 Intake, LS6 VCT, E^2 Catch Can, Hooker LTs and ORY, Magnaflow Cat-Back, 3" QTP electric cutout, UMI adj LCA, PHB, 3 pt SFCs, STB, MGW Shifter, SLP lid and bellow, Free-Mods, Tuned by BlueCat
Users Browsing this Thread
There are currently 1 users browsing this thread. (0 members and 1 guests)